题目
The area of a rectangular region enclosed by a wire is 1350 sq. yards. The length of the rectangular region is 15 yards more than the width of the region. What is the length of the wire in feet, required for fencing the rectangular region? (1 yard = 3 feet)
解析
设 \( w \) 为矩形的宽。
已知长比宽多15码,因此长 = \( w+15 \)
由于矩形的面积 = 宽 × 长,我们可以列出方程:
\( w \times (w + 15) = 1350 \)
\( w^2 + 15w = 1350 \)
\( w^2 + 15w - 1350 = 0 \)
\( (w + 45)(w - 30) = 0 \)
\( w = -45, 30 \)
因为宽度不能为负数,所以排除-45。由此可得宽为30码,长为 \( 30+15=45 \) 码。
要计算围起该区域所需的围栏长度,我们需要先算出周长,再将单位转换为英尺:
以码为单位的周长 = \( 2 \times (\text{宽}+\text{长}) \times 3 \text{ 英尺/码} = 2 \times (30\text{ 码}+45\text{ 码}) \times 3 = 450 \text{ 英尺} \)