题目

The numbers a, b and c form a sequence such that b is 3 more than a, and c is 9 more than b.


Also

Quantity A

b

Quantity B

选项

A.

Quantity A is greater.


B.

Quantity B is greater.


C.

The two quantities are equal.


D.

The relationship cannot be determined from the information given.

解析

已知: - \(b = a + 3\),即 \(a = b - 3\) - \(c = b + 9\) - 比例关系 \(\frac{a}{b} = \frac{b}{c}\),交叉相乘得 \(ac = b^2\) 代入 \(a\) 和 \(c\) 的表达式: \[ \begin{align*} (b - 3)(b + 9) &= b^2 \\ b^2 + 9b - 3b - 27 &= b^2 \\ b^2 + 6b - 27 &= b^2 \\ 6b &= 27 \\ b &= \frac{27}{6} = \frac{9}{2} \end{align*} \] 进一步可求得: - \(a = \frac{9}{2} - 3 = \frac{3}{2}\) - \(c = \frac{9}{2} + 9 = \frac{27}{2}\) 验证比例:\(\frac{a}{b} = \frac{3/2}{9/2} = \frac{1}{3}\),\(\frac{b}{c} = \frac{9/2}{27/2} = \frac{1}{3}\),等式成立。 **结论:答案为 A,\(b = \frac{9}{2}\)** ✅
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