题目
The numbers a, b and c form a sequence such that b is 3 more than a, and c is 9 more than b.
Also
选项
C.The two quantities are equal.
D.The relationship cannot be determined from the information given.
解析
已知:
- \(b = a + 3\),即 \(a = b - 3\)
- \(c = b + 9\)
- 比例关系 \(\frac{a}{b} = \frac{b}{c}\),交叉相乘得 \(ac = b^2\)
代入 \(a\) 和 \(c\) 的表达式:
\[
\begin{align*}
(b - 3)(b + 9) &= b^2 \\
b^2 + 9b - 3b - 27 &= b^2 \\
b^2 + 6b - 27 &= b^2 \\
6b &= 27 \\
b &= \frac{27}{6} = \frac{9}{2}
\end{align*}
\]
进一步可求得:
- \(a = \frac{9}{2} - 3 = \frac{3}{2}\)
- \(c = \frac{9}{2} + 9 = \frac{27}{2}\)
验证比例:\(\frac{a}{b} = \frac{3/2}{9/2} = \frac{1}{3}\),\(\frac{b}{c} = \frac{9/2}{27/2} = \frac{1}{3}\),等式成立。
**结论:答案为 A,\(b = \frac{9}{2}\)** ✅