
A utility company sells electricity to its customers by units of energy called kilowatt hours (kWh). In order to encourage its customers to use less electricity during periods of peak electrical demand in the summer, the company charges its customers a higher amount per kWh for electricity during peak usage times. The graph shows the amount, in USD per kWh, that the company charges its customers for electricity during both the summer and non-summer months, from the hours of 6:00 a.m. until 6:00 p.m. The utility company charges the same price per kWh in the summer and non-summer months for all hours of the day not depicted in the graph.
Select from each drop-down menu the option that creates the most accurate statement based on the information provided.
During the times depicted in the graph, the utility company charges customers more per kWh in the summer months than it does in the non-summer months, except during the hours from {【下拉选项标识】}, when the utility company charges {【下拉选项标识】} less per kWh than it charges during the non-summer months.
一家公用事业公司以千瓦时(kWh)为单位向客户销售电力。为了鼓励客户在夏季用电高峰期减少用电量,该公司在用电高峰期对每千瓦时电力收取更高的费用。该图表显示了从上午6:00到下午6:00,公司在夏季和非夏季月份对电力的收费金额(美元/千瓦时)。公用事业公司在图表未显示的所有其他时段,夏季和非夏季月份的每千瓦时价格相同。
从每个下拉菜单中选择一个选项,根据提供的信息创建最准确的陈述。
这个问题很简单。因此,只要仔细阅读图表、确保使用正确的信息并避免粗心错误,我们就能正确回答,为数据洞察部分赢得一些分数。
在图表显示的时间段内,公用事业公司在夏季月份对客户收取的每千瓦时费用高于非夏季月份,除了在__________时段,
查看图表上方的图例,我们看到蓝色柱形表示夏季费用,黑色柱形表示非夏季费用。因此,要找出公司夏季收费不高于非夏季的时段,我们需要找出蓝色柱形比黑色柱形短或与之等长的时段。
这样看,我们发现有三个时段蓝色柱形比黑色柱形短,没有时段两者的柱形长度相同。蓝色柱形较短的三个时段是上午6:00、7:00和8:00。
选择6:00 a.m.至8:59 a.m.
此时公用事业公司收取的费用比非夏季月份__________每千瓦时少。
要找到这个数值,我们计算相关时段夏季和非夏季费用的差额。
非夏季 - 夏季 = 差额
0.06 - 0.04 = 0.02
选择0.02美元。