题目
If x is the sum of the even integers from 200 to 600 inclusive, and y is the number of even integers from 200 to 600 inclusive, what is the value of x + y?
解析
答案:D
解答:
设\( y \)为200到600(包含两端)之间的偶数个数:
\[
\frac{600 - 200}{2} + 1 = 201 = y
\]
设\( x \)为200到600(包含两端)之间所有偶数的和:
\[
\frac{201}{2}×[200 + 600] = 201×400 = x
\]
因此\( x + y = 201 + 201×400 = 201×401 \)